Hardy-Weinberg

After given the q^2, I was able to find the  recessive allele (q) by square rooting the homozygous recessive individual. Next, I was able to find the dominant allele (p) by subtracting 1 by the recessive allele. Then, after finding the dominant allele i squared it to find the homozygous dominant individual. After that, I was able to find out what the heterozygous is so i multiplied 2 times dominant allele and recessive allele (2(p)(q)) . And i got 45. Finally, i multiplied the population by each individual. Therefore, .12 (q^2) times 1000 is 120, and .45 (p^2) times 1000 is 420. then 2pq will equal to 450.